(2x + 16) + (x) = 180
abcd is a quadrilateral inscribed in a circle
angle a is labeled x plus 16, (x + 16)
angle b is labeled x degrees, (x)
angle c is labeled 6x minus 4, (6x – 4)
angle d is labeled 2x plus 16, (2x + 16)
what equation can be used to solve for angle b?
we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.
angle b is opposite angle d
therefore, angle b + angle d = 180
(x) + (2x + 16) = 180
same as (2x + 16) + (x) = 180